![]() NOTE: -ve acceleration implies that body is decelerating or undergoing retardation.Ī car travels at 25 m/s.Driver suddenly applies brakes and car is brought to rest with uniform deceleration of 4 m/(s*s).Ĭalculate time taken for car to come to rest. Solution : Speed remains constant but the velocity changes continuously because the direction of motion is changing continuously.ĮQUATIONS OF MOTION FOR BODY MOVING WITH UNIFORM ACCELERATION: Problem:A car moves in a circular path at a constant speed at 10 m/s.What is its acceleration? Theory: A body is said to move with uniform velocity if it covers equal distances in equal time intervals while travelling along a straight line and in a specified direction. VELOCITY : rate of change of displacementĪCCELERATION : rate of change of velocity ( SI units: m/(s*s) Solution: Distance= speed*time = 5*(30*60) = 9000 mĪverage speed = Total dist/total time taken ![]() or give you access to the Github repository for you to push. If you find errata, do contact me so I can remedy. ![]() These notes are written by myself, which means they are prone to typos and errors. They might be similar in content to other physics courses too, though structured differently. Speed= Distance/time taken ( SI units: m/s ).EQUATION 1Įquation 1 can ONLY be used in cases where the body is moving with constant speed.Ī car moves at 5 m/s for half an hour.What is the distance travelled? These notes are for the O-Level Physics syllabus 6091. ![]()
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